A load of 54 N attached to a spring hanging vertically stretches the spring 4.9 cm. The spring is now placed horizontally on a table and stretched 14 cm.

What force is required to stretch it by this amount?

The spring constant is 54/4.9 N/cm.

Multiply that spring constant by the new deflection to get the force required.

!t should be (54/4.9)*14 cm

To find the force required to stretch the spring by a certain amount, we can use Hooke's law, which states that the force required to stretch or compress a spring is directly proportional to the displacement.

The formula for Hooke's law is given by:

F = k * x

Where:
F is the force applied to the spring
k is the spring constant
x is the displacement or change in length of the spring

In this case, we know the displacement (x) of the spring when a load of 54 N is attached vertically (4.9 cm), but we do not know the spring constant (k). However, we can calculate the spring constant using the given information.

First, convert the displacement from centimeters (cm) to meters (m):
x = 4.9 cm = 4.9/100 m = 0.049 m

Next, we can determine the spring constant (k) using the formula:
k = F / x

Substituting the known values:
k = 54 N / 0.049 m

Calculating:
k ≈ 1102.04 N/m

Now that we have found the spring constant (k) for this particular spring, we can use it to find the force required to stretch the spring horizontally.

Given that the displacement (x) is 14 cm, convert it to meters:
x = 14 cm = 14/100 m = 0.14 m

Using Hooke's law:
F = k * x

Substituting the values we have:
F = 1102.04 N/m * 0.14 m

Calculating:
F ≈ 154.29 N

Therefore, the force required to stretch the spring by 14 cm when it is placed horizontally on a table is approximately 154.29 N.