13.98mL of 2.902M HCl are reacted with 15mL of 3.198M NaOH. Use the molar heat of neutralization to determine the kJ of heat produced.
What is the molar heat of neutralization?
the molar heat of neutralization is -55.84kJ/mol
moles NaOH = M x L(this is in excess)
moles HCl = M x L(limiting reagent)
moles HCl reacted x 55.84 kJ/mol = xx kJ heat released.
To determine the kJ of heat produced in this reaction, we need to first calculate the moles of HCl and NaOH that are reacted. Then, we can use the molar heat of neutralization to determine the heat produced.
Step 1: Calculate the moles of HCl and NaOH used.
The volume and concentration are given for both HCl and NaOH.
Moles of HCl = Volume of HCl (in L) × Concentration of HCl (in mol/L)
Moles of HCl = 13.98 mL × (1 L/1000 mL) × 2.902 mol/L
Moles of NaOH = Volume of NaOH (in L) × Concentration of NaOH (in mol/L)
Moles of NaOH = 15 mL × (1 L/1000 mL) × 3.198 mol/L
Step 2: Determine the limiting reactant.
Compare the moles of HCl and NaOH to determine which one is the limiting reactant. The reactant that is completely consumed will limit the amount of product formed.
Step 3: Use the balanced chemical equation and the limiting reactant to calculate the moles of water produced.
From the balanced chemical equation, we know that 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of water.
Step 4: Use the molar heat of neutralization to determine the heat produced.
The molar heat of neutralization is the amount of heat released when 1 mole of a substance is neutralized with the base, typically measured in kilojoules per mole (kJ/mol).
Multiply the moles of water produced by the molar heat of neutralization to determine the kJ of heat produced.
Make sure to check the units and cancel out the appropriate units during calculations to get the final answer in kJ.
Note: The molar heat of neutralization for the reaction between HCl and NaOH is typically -57 kJ/mol.