One synthetic preparation of aniline involves reducing nitrobenzene with iron and HCL, and then steam distilling the resultant aniline at 99C. How much aniline codistills with each gram of water during steam distillation?

I do not know how to get the molecular weight for the aniline in this problem.
I know that
mass oil/mass water = (Poil)(MW oil) + (Pwater)(MW water) and that the Vapor pressure of water at 99 °C = 733 mmHG, so all I'm really missing is the Molecular weight but how can i solve it??

To determine the molecular weight of aniline, we can use the periodic table to find the atomic masses of the elements in aniline and then add them up.

Aniline, also known as phenylamine, has the molecular formula C6H5NH2.

To find the molecular weight, we need to calculate the sum of the atomic masses of carbon (C), hydrogen (H), nitrogen (N), and a single molecule of amine (-NH2). The atomic masses can be found on the periodic table.

The atomic mass of carbon (C) is 12.01 grams/mole, the atomic mass of hydrogen (H) is 1.008 grams/mole, and the atomic mass of nitrogen (N) is 14.01 grams/mole.

Since there are two hydrogen atoms in the amine group, we need to multiply the atomic mass of hydrogen by 2.

So, the molecular weight of aniline is:

(6 * C) + (5 * H) + (1 * N) + (2 * H)
= (6 * 12.01) + (5 * 1.008) + (1 * 14.01) + (2 * 1.008)
= 72.06 + 5.04 + 14.01 + 2.016
= 93.126 grams/mole

Therefore, the molecular weight of aniline is approximately 93.126 grams/mole.

With the molecular weight of aniline determined, you can now proceed to calculate how much aniline codistills with each gram of water during steam distillation using the equation you provided:

mass oil/mass water = (Poil)(MW oil) + (Pwater)(MW water)

Given that the vapor pressure of water at 99 °C is 733 mmHg, you can substitute the values into the equation and solve for mass oil (aniline) per gram of water.