Compute the freezing point of this Solution:

25.5g C7H11NO7S (4-nitro-2-toluenesulfonoic acid dihydrate) in 1.00*10^2g H2O (nonionizing solute)

The freezing point of H2O is lowered 1.86 Celsius per mole of solute.

The boiling point of H2O is raised 0.512 Celsius per mole of solute.

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To compute the freezing point of the solution, you need to use the formula for freezing point depression:

ΔTf = Kf* m

Where:
ΔTf = change in freezing point
Kf = cryoscopic constant (freezing point depression constant) for the solvent (water in this case)
m = molality of the solution

First, you need to calculate the molality of the solution, which is the number of moles of the solute per kilogram of the solvent.

1. Calculate the moles of solute (C7H11NO7S):
Molar mass of C7H11NO7S = 225.23 g/mol
Moles of C7H11NO7S = mass / molar mass
= 25.5 g / 225.23 g/mol

2. Calculate the mass of the solvent (water):
Mass of H2O = 1.00*10^2 g

3. Calculate the molality (m):
Molality (m) = moles of solute / mass of solvent (in kg)
= (25.5 g / 225.23 g/mol) / (1.00*10^2 g / 1000 g/kg)

Now that you have the molality (m), you can calculate the change in the freezing point (ΔTf) using the cryoscopic constant (Kf) of water. The cryoscopic constant for water is 1.86 °C/m.

4. Calculate the change in freezing point (ΔTf):
ΔTf = Kf * m
= 1.86 °C/m * molality (m)

Therefore, the freezing point of the solution can be calculated by subtracting the change in freezing point (ΔTf) from the freezing point of pure water (0 °C).

5. Freezing point of the solution:
Freezing point = 0 °C - ΔTf

By substituting the calculated values into the formula, you can obtain the freezing point of the solution.

Compute the boiling point of this solution 25.5g C7H11NO7S

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