In a crash test, a truck with mass 2600 kg traveling at 24 m/s smashes head-on into a concrete wall without rebounding. The front end crumples so much that the truck is 0.66 m shorter than before.

What is the average speed of the truck during the collision (that is, during the interval between first contact with the wall and coming to a stop)?
Vavg = m/s
About how long does the collision last? (That is, how long is the interval between first contact with the wall and coming to a stop)?
Delta T = s
What is the magnitude of the average force exerted by the wall on the truck during the collision?
|Favg| = N
It is interesting to compare this force to the weight of the truck. Calculate the ratio of the force of the wall to the gravitational force on the truck. This large ratio shows why a collision is so damaging.
|Favg|/(mg) =

i need help with how to find average force

To find the average speed of the truck during the collision, you need to calculate the change in velocity.

Given:
Initial velocity (vi) = 24 m/s
Final velocity (vf) = 0 m/s

Average speed (Vavg) is defined as the total distance traveled divided by the total time taken. In this case, we need to find the distance traveled during the collision.

Given:
Change in length (ΔL) = 0.66 m

The distance traveled can be calculated by subtracting the change in length from the initial length of the truck. Let's assume the initial length of the truck is L.

Distance traveled = L - ΔL

Since the truck smashes head-on into a concrete wall without rebounding, it stops completely. Therefore, the distance traveled during the collision is equal to the change in length of the truck.

Therefore, Distance traveled = ΔL = 0.66 m

To calculate the average speed, divide the distance traveled by the time taken:

Vavg = ΔL / Δt

Now, let's move on to finding the time duration of the collision (Δt).

We can use the formula for average speed to solve for time:

Vavg = (vi + vf)/2

Rearranging the formula, we get:

Δt = 2 * ΔL / (vi + vf)

Let's substitute the given values:

Δt = 2 * 0.66 m / (24 m/s + 0 m/s)

Now, to find the magnitude of the average force exerted by the wall on the truck during the collision, we can use Newton's second law of motion:

Force (F) = mass (m) * acceleration (a)

Since the truck comes to a stop, the average acceleration can be calculated by dividing the change in velocity by the time taken:

a = (vf - vi) / Δt

Substituting the given values:

a = (0 m/s - 24 m/s) / Δt

Finally, substituting this acceleration into Newton's second law equation, we can find the magnitude of the average force (|Favg|) exerted by the wall on the truck:

|Favg| = m * a

To calculate the ratio of the force of the wall to the gravitational force on the truck, divide the magnitude of the average force (|Favg|) by the weight of the truck (mg).

|Favg| / (mg) = |Favg| / (m * g)

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Now, you can plug in the given values to calculate the average speed of the truck, the time duration of the collision, the magnitude of the average force, and the ratio of the force to the gravitational force.