Please let me know how you would approach the gas law problem. Here goes:
If the pressure exerted on the gas in a weather ballon decreases from 1.01 atm to 0.562 atm as it rises. By what factor will the volume of the gas in the ballon increase as it rises?
I can't seem to figure out which gas law mathematical equation to apply.
Thanks for being helpful.
It's just P and V; therefore,
P1V1 = P2V2 and you want to solve for V1/V2
To solve this problem, we can use the combined gas law equation, which combines Boyle's Law, Charles's Law, and Gay-Lussac's Law. The equation is:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 and P2 are the initial and final pressures of the gas,
V1 and V2 are the initial and final volumes of the gas,
T1 and T2 are the initial and final temperatures of the gas.
However, in this problem, we are given only the pressure values and asked to find the volume change. Therefore, we can simplify the equation to:
P1 * V1 = P2 * V2
Now, let's plug in the given pressure values:
P1 = 1.01 atm
P2 = 0.562 atm
The equation now becomes:
1.01 atm * V1 = 0.562 atm * V2
To find the factor by which the volume increases, we can isolate V2 by dividing both sides of the equation by 0.562 atm:
V2 = (1.01 atm * V1) / 0.562 atm
Now, we can simplify:
V2 = 1.7982 * V1
This means that the volume of the gas in the balloon will increase by a factor of 1.7982 (or approximately 1.8) as it rises.
I hope this explanation helps! Let me know if you have any further questions.