y varies jointly with p and q. When p = 12 and q = 4, y = 144. Find y when p = 10 and q = 6.
p = 12, q = 4, y = 144.
y = kpq,
y = k*12*4 = 144,
k*12*4 = 144,
48k = 144,
k = 144/48 = 3.
Check: y = 3*12*4 = 144.
p=10, q = 6.
y = kpq = 3 * 10 * 6 = 180.
To find the value of y when p = 10 and q = 6, we need to use the given information that y varies jointly with p and q. When two variables vary jointly, it means that their relationship is characterized by a constant of proportionality.
In this case, we have y = k * p * q, where k is the constant of proportionality.
We can find the value of k by substituting the values of p, q, and y from the first scenario:
144 = k * 12 * 4
To find k, divide both sides of the equation by (12 * 4):
k = 144 / (12 * 4)
k = 3
Now that we have the value of k, we can substitute it into the equation to find the value of y when p = 10 and q = 6:
y = 3 * 10 * 6
y = 180
Therefore, when p = 10 and q = 6, y = 180.