What is the solution set for |–2x + 16| – 9 = –3
[-2x + 16 ] - 9 = - 3.
[-2x + 16] = 9 - 3,
[-2x + 16] = 6,
The number whose absolute value = 6 can
be (+-):
+-(-2x + 16) = 6,
+(-2x + 16 = 6,
-2x + 16 = 6,
-2x = 6 - 16,
-2x = - 10,
x = - 10 / -2 = 5.
-(-2x + 16) = 6,
2x - 16 = 6,
2x = 6 + 16,
2x = 22,
x = 22 / 2 = 11.
Solution set: x = 5, and x = 11.