posted by Oddbjørn
Hi I have a question in Physics
A block with mass 50kg is held on a slope. Ù friction coefficient = 0.35 between the plane and the block ..
Planets angle v with the horizontal is 25 degrees. How far will the block slide down the plane in 5 seconds after it is released (in meters)?
Thanks for the answer
Ordbok - Vis detaljert ordbokresultat
Var sa god
FORCE COMPONENT DOWN SLOPE = M G SIN 25
NORMAL FORCE ON BLOCK = M G COS 25
FRICTION FORCE UP SLOPE = mu M G cos 25
F = Net force down slope = M G sin 25 - mu M G cos 25
Calculate that F
a = F/M
d = 0 + 0 t + (1/2) a t^2