Given the following equation: NH3 +O2 �¨ NO + H2O
Calculate the number of grams of ammonia needed to form 40.12 moles of nitrogen monoxide.
ok so is this how its to look
4(NH3) + 5(O2) --> 4NO + 6(H20)
ok, you want 40moles of NO, so the ratio of ammonia to NO is 4:4, so you need 40 moles NH3. Convert that to grams.
Yes, you need to do it more accurately.
so then would it look like N= 14.01 and h= 1.008 add them and times by 40?
To calculate the number of grams of ammonia needed to form 40.12 moles of nitrogen monoxide, we can use the balanced chemical equation:
4NH3 + 5O2 → 4NO + 6H2O
First, we need to find the molar mass of NH3 (ammonia). The molar mass of nitrogen (N) is approximately 14.01 g/mol, and the molar mass of hydrogen (H) is approximately 1.01 g/mol. Since there are three hydrogen atoms in ammonia, we multiply the molar mass of hydrogen by 3 and add it to the molar mass of nitrogen to get the molar mass of NH3:
Molar mass of NH3 = 14.01 g/mol + 1.01 g/mol * 3 = 17.04 g/mol
Next, we use the coefficient of NH3 from the balanced equation (4) and the molar mass of NH3 to convert moles of NO to grams of NH3:
40.12 moles of NO * (4 moles of NH3 / 4 moles of NO) * (17.04 g/mol of NH3 / 1 mole of NH3) = 40.12 * 17.04 g
Calculating this expression will give you the number of grams of ammonia needed to form 40.12 moles of nitrogen monoxide.