How many mL of concentrated ammonia (14M) should be diluted to 250 mL to make a 0.75 M NH3 solution?
you are diluting it 14/.75= 14*4/3= 18 2/3 times. That means one part original stuff, 17 2/3 parts water.
what is one part? 250ml/(18.6666)=13.393 ml
so 13.392 ml of 14M conc ammonia
and 17 2/3 x 13.392=236.607ml water.
what the i dont get it
To calculate the volume of concentrated ammonia required to make a 0.75 M NH3 solution, we can use the formula:
\(M_1 \times V_1 = M_2 \times V_2\)
Where:
\(M_1\) = initial concentration of ammonia
\(V_1\) = volume of ammonia to be diluted
\(M_2\) = final concentration of ammonia
\(V_2\) = final volume of ammonia solution
Given:
\(M_1\) = 14 M (concentration of concentrated ammonia)
\(V_1\) = unknown
\(M_2\) = 0.75 M (final concentration of ammonia solution)
\(V_2\) = 250 mL (final volume of ammonia solution)
Substituting the given values into the formula, we can solve for \(V_1\):
\(14 \times V_1 = 0.75 \times 250\)
Simplifying the equation:
\(V_1 = \frac{0.75 \times 250}{14}\)
Calculating \(V_1\):
\(V_1 = 13.39 \, \text{mL}\)
Therefore, you will need to dilute approximately 13.39 mL of concentrated ammonia to 250 mL in order to make a 0.75 M NH3 solution.
To determine the volume of concentrated ammonia solution (14M) that needs to be diluted to obtain a 0.75 M NH3 solution, we can use the equation:
C1 * V1 = C2 * V2
Where:
C1 = initial concentration of the ammonia solution (14M)
V1 = volume of the ammonia solution to be diluted (unknown)
C2 = final concentration of the NH3 solution (0.75M)
V2 = final volume of the NH3 solution (250mL)
Plugging in the values, we get:
14M * V1 = 0.75M * 250mL
Now, let's solve for V1:
V1 = (0.75M * 250mL) / 14M
V1 = (0.75 * 250) / 14
V1 ≈ 13.39 mL
Therefore, approximately 13.39 mL of the concentrated ammonia (14M) should be diluted to 250 mL to make a 0.75 M NH3 solution.