An ideal gas (volume 1.1m3 , pressure 101500 Pa, temperature 290 K) undergoes an isothermal process during which it absorbs 2000 J of heat. How much did the entropy of the system increase?

To find the change in entropy of the system during an isothermal process, you can use the equation:

ΔS = Q/T

Where:
ΔS is the change in entropy
Q is the heat absorbed or released by the system
T is the temperature at which the process occurs

Using the given values:
Q = 2000 J
T = 290 K

Substituting these values into the equation, we get:

ΔS = 2000 J / 290 K
ΔS ≈ 6.90 J/K

Therefore, the change in entropy of the system is approximately 6.90 J/K.