To dilute a solution from 0.600 M to 0.100 M, the final volume must be
A. 1/6 the original volume.
B. 0.7 L.
C. More information is needed to answer this question.
D. 6 times the original volume.
E. 60 L.
d
The concentration of Pb2+ in a sample of wastewater is to be determined by using gravimetric analysis. To a 100.0-mL sample of the wastewater is added an excess of sodium carbonate, forming the insoluble lead (II) carbonate (267 g/mol) according to the balanced equation given below. The solid lead (II) carbonate is dried, and its mass is measured to be 0.1443 g. What was the concentration of Pb2+ in the original wastewater sample?
Pb2+(aq) + Na2CO3(aq) → PbCO3(s) + 2Na+(aq)
Group of answer choices
To dilute a solution, you need to add a solvent to decrease the concentration of the solution. The formula for dilution is:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, the initial concentration (C1) is 0.600 M and the final concentration (C2) is 0.100 M. The goal is to find the final volume (V2).
From the formula, we can rearrange it to solve for V2:
V2 = (C1V1) / C2
Let's plug in the given information:
C1 = 0.600 M
V1 = ?
C2 = 0.100 M
Since the initial volume (V1) is not given, we cannot directly calculate the final volume (V2). Therefore, the answer is:
C. More information is needed to answer this question.
Just pick a number like 100 mL
mL x M = mL x M
100 x 0.6 = mL x 0.1
Solve for mL and I get
100*0.6/0.1 = 600
600 mL is what times 100?