posted by Stacey .
Wrtie the equilibrium constant expression for the reaction of NH3 with water. the OH- concentration of .050 M ammonia, NH3, is 9.5 x 10^-4 M
NH3(aq) ==> NH4^+ + OH^-
K = (NH4^+)(OH^-)/(NH3)
This is the expression; I don't know what the numerical values mean.