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A Ferris wheel with radius 9.8 m rotates at a constant rate, completing one revolution every 36.6 s. Suppose the Ferris wheel begins to decelerate at the rate of 0.227 rad/s2 when a passenger is at the top of the wheel. Find the magnitude and direction of the passenger's acceleration at that time.


direction______° below direction of travel

  • Physics -

    first find angular speed
    w=(2pi)/36.6 to get rad/s
    then, you must find a(cp) and a(tangential)
    at=r*alpha =>9.8*-.227
    use a=sqrt(acp^2+at^2)
    the answer is the magnitude

    to find the angle use tan^-1(acp/at)

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