A stationary 25kg object is located on a table near the surface of the earth. The coefficient of kinetic friction between the surface is 0.30. Determind the acceleratin of the object.

if it is stationary, it has no acceleration.

can u explain

if something is stationary, it does not move. acceleration means the change of velocity per time, and the change of velocity for a stationary object is zero.

oh and the Ffr is 73.5N and the horizontal force is 300N

To determine the acceleration of the object, we need to consider the forces acting on it. In this case, there are two main forces: the force of gravity pulling the object downward and the force of friction opposing the object's motion.

To start, let's calculate the force of gravity acting on the object. The force of gravity can be calculated using the equation:

F_gravity = m * g

where m is the mass of the object and g is the acceleration due to gravity. In this case, the mass of the object is given as 25kg, and the acceleration due to gravity is approximately 9.8 m/s^2.

F_gravity = 25 kg * 9.8 m/s^2
= 245 N

Now, let's calculate the force of friction. The force of friction can be calculated using the equation:

F_friction = μ * N

where μ is the coefficient of kinetic friction and N is the normal force. The normal force is the force exerted by the surface on the object and is equal in magnitude and opposite in direction to the force of gravity.

In this case, the coefficient of kinetic friction is given as 0.30. To calculate the normal force, we can use the equation:

N = m * g

N = 25 kg * 9.8 m/s^2
= 245 N

Now we can calculate the force of friction:

F_friction = 0.30 * 245 N
= 73.5 N

Since the object is stationary, it means that the force of friction is equal in magnitude and opposite in direction to the force of gravity:

F_friction = - F_gravity

Thus, we have:

73.5 N = - 245 N

To determine the acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration:

Net Force = m * a

In this case, the net force is given by the force of friction:

Net Force = F_friction = 73.5 N

Therefore:

m * a = 73.5 N

Substituting the mass of the object:

25 kg * a = 73.5 N

Solving for the acceleration:

a = 73.5 N / 25 kg
= 2.94 m/s^2

So, the acceleration of the object is approximately 2.94 m/s^2.

but my teeacher said since Ffr is less then the horizontal force it has accelerations