Solve for x:9x^2-49=0
SIMPLE! add 49 to the other side-
9x^2=49
Now take the square root of 49. I'm in 10th grade, isnt this easy? maybe im doing it wrong?
9x^2=49
3x=7
x=7/3
stupid 10th grader
positive or negative 7/3
stupid whoever u are
X equals minus seven over 3 or seven over three. We've been dealing with this in my school so I'm certain as death about it.
-+7/3
To solve for x in the equation 9x^2 - 49 = 0, we can use the method of factoring the polynomial or using the quadratic formula.
Let's use the factoring method:
1. Start by recognizing that 9x^2 - 49 can be written as a difference of squares, where 49 is a perfect square (7^2).
2. Rewrite the equation as (3x)^2 - 7^2 = 0. This follows the pattern a^2 - b^2 = (a + b)(a - b).
3. Applying the difference of squares formulas, we have (3x + 7)(3x - 7) = 0.
4. Set each factor equal to zero:
3x + 7 = 0 or 3x - 7 = 0
5. Solve for x in each equation:
For 3x + 7 = 0, subtract 7 from both sides: 3x = -7. Then divide both sides by 3: x = -7/3.
For 3x - 7 = 0, add 7 to both sides: 3x = 7. Divide both sides by 3 to get: x = 7/3.
Thus, the solutions for the equation 9x^2 - 49 = 0 are x = -7/3 and x = 7/3.