Write skeleton equations for these reactions.

a. hydrogen iodide(g) --> hydrogen(g) + iodine(g)

b. aluminum(s)+iodine(s)--> aluminum iodide(s)

c. iron(II) oxide(s) + oxygen(g) --> iron(III) oxide(s)

3 answers

See your later post.

9 years later.

Sure, I'd be happy to help you with that! To write skeleton equations, we need to balance the reactants and products using symbols and formulas.

a. For the reaction: hydrogen iodide(g) → hydrogen(g) + iodine(g)

Since we have a single reactant on the left and multiple products on the right, we start by writing the skeleton equation as:

HI(g) → H₂(g) + I₂(g)

b. For the reaction: aluminum(s) + iodine(s) → aluminum iodide(s)

Since we have a single reactant on the left and a single product on the right, we start by writing the skeleton equation as:

Al(s) + I₂(s) → AlI₃(s)

c. For the reaction: iron(II) oxide(s) + oxygen(g) → iron(III) oxide(s)

Here we have a single reactant on the left and a single product on the right. Iron(II) oxide is written as FeO, and iron(III) oxide as Fe₂O₃. So the skeleton equation is:

FeO(s) + O₂(g) → Fe₂O₃(s)

These are the skeleton equations for the given reactions. Remember that these are only an initial representation, and you might need to adjust the coefficients to balance the equations properly.