how many equivalents of sulfuric acid are in 20mL of 0.35 N H2SO4 solution? How many grams?
normality = #milliequivalents/mL = #me/mL
Subsitute N and mL, solve for #me and convert to equivalents.
Solve for grams remembering that 1 equilvalent H2SO4 = 49 g
To determine the number of equivalents (Eq) of sulfuric acid (H2SO4) in the solution and the corresponding grams, you will need to use the equation:
Eq = (volume in liters) × (normality)
First, convert the volume from milliliters to liters:
20 mL = 20/1000 = 0.02 liters
Now, substitute the values into the equation:
Eq = 0.02 L × 0.35 N
Eq = 0.007 Eq
To calculate the grams, you will need to know the molar mass of sulfuric acid (H2SO4), which is 98.09 g/mol.
Now, use the equation:
grams = (equivalents) × (molar mass)
Substitute the values into the equation:
grams = 0.007 Eq × 98.09 g/mol
grams = 0.686 g
Therefore, there are 0.007 equivalents of sulfuric acid in 20 mL of 0.35 N H2SO4 solution, which is equivalent to 0.686 grams.
To determine the number of equivalents of sulfuric acid in a given solution, we need to understand the concept of equivalents. An equivalent is a unit of the amount of a substance that is capable of reacting with one mole of hydrogen ions (H+).
To find the number of equivalents of sulfuric acid in the solution, you can use the formula:
Equivalents = Normality × Volume (in liters)
First, let's convert the volume from milliliters to liters:
20 mL = 20/1000 = 0.02 L
Now we can calculate the number of equivalents:
Equivalents = 0.35 N × 0.02 L = 0.007 equivalents
To determine the number of grams of sulfuric acid in the given solution, we need to understand the concept of molarity.
Molarity (M) is the number of moles of solute per liter of solution. For sulfuric acid (H2SO4), the molar mass is 98.09 g/mol.
To calculate the number of grams, we can use the formula:
Grams = Molarity × Volume (in liters) × Molar mass
Using the values given:
Grams = 0.35 N × 0.02 L × 98.09 g/mol = 0.686 grams
Therefore, there are 0.007 equivalents of sulfuric acid and 0.686 grams of sulfuric acid in 20 mL of 0.35 N H2SO4 solution.