the length of the top of a table is 3 m greater than the width. the area is 88m^2. find the dimensions of the table

L = W + 3

L * W = 88

Substitute W+3 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.

To find the dimensions of the table, we'll use two equations: one for the relationship between the length and width, and another for the area of the table.

Let's say the width of the table is "x" meters. According to the given information, the length is 3 meters greater than the width, so the length would be "x + 3" meters.

The area of a rectangle is calculated by multiplying its length by its width. In this case, the area of the table is given as 88 square meters. Therefore, we have the equation:

Length * Width = Area

Substituting the values we know, we get:

(x + 3) * x = 88

Expanding the equation, we have:

x^2 + 3x = 88

Rearranging the equation in standard quadratic form, we have:

x^2 + 3x - 88 = 0

Now, we can solve this equation by factoring, completing the square, or using the quadratic formula. Let's use factoring:

(x - 8)(x + 11) = 0

So, either x - 8 = 0 or x + 11 = 0.

If we solve for x in both cases, we get:

x = 8 or x = -11

Since the width cannot be negative, we discard x = -11. Therefore, the width of the table is 8 meters.

To find the length, we add 3 to the width:

Length = Width + 3 = 8 + 3 = 11 meters

Therefore, the dimensions of the table are 8 meters for the width and 11 meters for the length.