i had posted this question about a week ago and had gotten help from bobpursley(thank you so much btw) but i was showed how to do it using an equationa and now when im studying for the test i realize i need to be able to make a conversion factor to solve it. so heres the problem:
Silver chloride, often used in silver plating, contains 75.27% Ag. Calculate the mass of silver chloride in grams required to make 4.7 g of silver plating.
the equation bob showed me before was
7527*x=4.7g
solve for x
Im just looking how to solve it using a conversion factor. I tried to make one but i didn't know what to do. thanks
mols Ag needed = grams/molar mass = 4.7/107.9 = 0.04356
moles AgCl = moles Ag x (1 mole AgCl/1 mole Ag) = 1 mole AgCl
g AgCl = moles x (143.34/1 mole) = 0.04356*(143.32) =6.24 grams AgCl.
Note 0.7527*x = 4.7
s = 6.24 grams.
You can string those above into one line and cancel a lot of terms and end up with a conversion factor that is very convenient (its called a chemical factor BUT most profs don't teach it anymore--I used it a great deal when I was a student). It's done this way. We will let MM stand for molar mass.
(g Ag/MM Ag) x (1 mol AgCl/1 mol Ag) x (MM AgCl/1 mol AgCl) =
g Ag x (MM AgCl/MM Ag) = 4.7*(143.32/107.9) = 6.24 g.
You can convert grams of one thing to grams of anything else by using the appropriate chemical factor. In this case, the CF is (143.32/107.9) which is just the ratio of the molar mass of what you want to convert to divided by the molar mass of the starting material.
For example, to convert 2.5 g Mg to grams of Mg2P2O7, we write
2.5 x (molar mass Mg2P2O7/2*molar mass Mg) = 2.5 x (222.55/48.61) = ??. Note I multiplied the Mg by 2 in order to convert to the same number of moles of the metal.
Convert 3.0 g As to As2O5 would be
3.0 x (molar mass As2O4/2*molar mass As) = ??
thanks!!!
To solve the problem using a conversion factor, you need to set up a ratio between the two substances involved: silver chloride and silver plating.
Step 1: Identify the given information:
- The percentage of silver in silver chloride: 75.27%
- The mass of silver plating: 4.7 g
Step 2: Set up the conversion factor using the given information:
Since silver chloride contains 75.27% silver, this means that 100% - 75.27% = 24.73% of silver chloride is comprised of chlorine.
- The conversion factor can be set up as follows:
1 g silver chloride / 75.27% silver = x g silver chloride / 100%
Step 3: Find the mass of silver chloride needed:
To find the mass of silver chloride needed to make 4.7 g of silver plating, set up the conversion factor as follows:
4.7 g silver plating * (x g silver chloride / 1 g silver chloride) = mass of silver chloride needed
Step 4: Apply the conversion factor:
Using the ratio from the conversion factor, you can set up the equation to solve for the mass of silver chloride.
4.7 g silver plating * (x g silver chloride / 1 g silver chloride) = mass of silver chloride needed
Step 5: Solve for x:
To solve for x, you can cross-multiply and divide:
4.7 g silver plating * x g silver chloride = mass of silver chloride needed
mass of silver chloride needed = (4.7 g silver plating * x g silver chloride) / 1 g silver chloride
Now, you have the equation set up to solve for x in terms of the mass of silver chloride needed.