Algebra HELP
posted by Amy .
how to solve this equation in the real number system:
2x^(3) + 3x^(2) + 2x + 3 = 0
steps please

2X^3 + 3X^2 + 2X + 3 = 0.
First, we reduce the cubic Eq to a guadratic Eq by finding a value of x that satisfies the Eq. This was done by
trial and error. However, the task was made a lot easier by the use of EXCEL Spread sheets.
It was determined x = 1.5 satisfies the cubic Eq:
x = 1.5 = 1 1/2 = 3/2.
x = 3/2,
x + 3/2 = 0,
Multiply both sides by 2 and get:
2x + 3 = 0.
Using long division, we divide the cubic Eq by 2x + 3:
(2x^3 + 3x^2 +2x + 3)/(2x + 3)=
x^2 + 1.
Now we can easily solve the quad. Eq:
x^2 + 1 = 0,
x2 = 1,
x = sqrt(1) = + i.
Solution set: x =  3/2, x = i, x = i.
So there are 3 solutions which is the max. for a cubic Eq.
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Math check please
1. Solve the system of equations y=2x^23 y=3x1 a)no solution b)(1/2,5),(2,5/2) c)(1/2,5/2),(2,5)**** d)(1/2,5/2),(2,5) 2. How many real number solutions are there to the equation 0=3x^2+x4?