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how many liters H2O need for incineration 25 L C3H8
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I don't know how you propose to incinerate C3H8 with water.
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Given the reaction: C3H8(g) + 5O2(g) �¨ 3CO2(g) + 4H2O(g)
What is the total volume of H2O(g) formed when 8.00 liters of C3H8(g)
Top answer:
When dealing with gases one may dispense with changing everything to moles. Volumes are
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C3H8+5 o2 - 3CO2 +4H2O the reaction
If I have 56.7 liters of o2 reacted, how many liters of H2O were produced?
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To find the number of liters of H2O produced in the reaction, we need to determine the ratio of
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In the following reaction, how many liters of oxygen will react with 124.5 liters of propane (C3H8), at STP?
C3H8 + 5O2 = 3CO2 +
Top answer:
Since all are gases one may use a shortcut that tells us we can use liters directly as moles. All
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For the reation: C3H8+5 02 =3 CO2+4 H2O
How many moles of C3H8 are needed to make 3.60 grams of H2O? I think the ans is 0.05
Top answer:
right
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Among the following equations, which one is in a balanced state?(1 point)
Responses C3H8 + 11 O2 → 3 CO2 + 8 H2O C 3 H 8 + 11 O
Top answer:
The equation that is in a balanced state is: C3H8 + 5 O2 → 3 CO2 + 4 H2O
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Among the following equations, which one is in a balanced state?(1 point)
Responses 2 C3H8 + 4 O2 → 2 CO2 + 4 H2O 2 C 3 H 8 + 4
Top answer:
The equation that is in a balanced state is: 2 C3H8 + 4 O2 → 2 CO2 + 4 H2O
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Among the following equations which one of them is in a balanced state
C3H8+3 O2 --> CO2 + CH2O C3H8 + 11 O2 --> 3 CO2 + 8 H2O
Top answer:
The equation that is in a balanced state is: 2 C3H8 + 4 O2 --> 2 CO2 + 4 H2O
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For the reation: C3H8+5 02 =3 CO2+4 H2O
How many moles of C3H8 are needed to make 3.60 grams of H2O? I think the ans is
Top answer:
To determine the number of moles of C3H8 required to produce 3.60 grams of H2O, you need to use the
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For the reation: C3H8+5 02 =3 CO2+4 H2O
How many moles of C3H8 are needed to make 3.60 grams of H2O? I think the ans is
Top answer:
No. That isn't right. Convert 3.60 g H2O to moles, convert that to moles C3H8.
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C3H8+5O2=3CO2+H2O How many liters of propaine (d=0.585g/ml) will produce 1.25L of water (d=1.00g/mL)?
Top answer:
First you balance the equation. C3H8 + 5O2 ==> 3CO2 + 4H2O 1.25L H2O with density 1.00 g/mL = 1,250
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The combustion of propane (C3H8) produces CO2 and H2O:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 3.5 mol of O2
Given the equation C3H8+5O2->3CO2+4H2O.
1.)Suppose 1.5 moles of C3H8 will be used, How many moles of H2O and CO2 will be formed?
How do you balance:
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