How much iron can be recovered from 25.0 grams of FeO?

Convert 25.0 g FeO to moles. moles = grams/molar mass.

Convert moles FeO to moles Fe (1:1 so that shouldn't be a problem.)

Convert moles Fe to grams Fe. g = moles x molar mass.

To calculate the amount of iron that can be recovered from 25.0 grams of FeO, we need to consider the molar mass of FeO and use stoichiometry.

1. Determine the molar mass of FeO.
- The molar mass of Fe (iron) is 55.845 g/mol.
- The molar mass of O (oxygen) is 16.00 g/mol.
- To find the molar mass of FeO, add the molar masses of iron and oxygen: 55.845 g/mol + 16.00 g/mol = 71.845 g/mol.

2. Calculate the number of moles of FeO in 25.0 grams.
- To convert grams to moles, divide the mass by the molar mass:
Moles of FeO = 25.0 g / 71.845 g/mol ≈ 0.3485 mol (rounded to four decimal places).

3. Use the balanced chemical equation to determine the ratio of moles of FeO to moles of Fe.
The balanced chemical equation for the reaction of FeO to produce Fe is:
2 FeO → 2 Fe + O2

From the equation, we can see that 2 moles of FeO produce 2 moles of Fe.

4. Calculate the moles of Fe that can be obtained from the given moles of FeO.
Since the ratio of FeO to Fe is 2:2 (or 1:1), the number of moles of Fe obtained will be the same as the number of moles of FeO.

Moles of Fe = 0.3485 mol (from step 2).

5. Calculate the mass of Fe that can be recovered.
To calculate the mass of Fe in grams, multiply the moles of Fe by the molar mass of Fe:
Mass of Fe = Moles of Fe × Molar mass of Fe
= 0.3485 mol × 55.845 g/mol ≈ 19.4 grams (rounded to one decimal place).

Therefore, approximately 19.4 grams of Fe can be recovered from 25.0 grams of FeO.

To calculate the amount of iron that can be recovered from FeO, we need to consider the molar mass of FeO and use stoichiometry.

1. Determine the molar mass of FeO:
The molar mass of iron (Fe) is 55.845 g/mol, and the molar mass of oxygen (O) is 15.999 g/mol. FeO consists of one iron atom and one oxygen atom, so the molar mass of FeO is 55.845 g/mol + 15.999 g/mol = 71.844 g/mol.

2. Find the number of moles of FeO:
Using the given mass of FeO (25.0 grams) and its molar mass (71.844 g/mol), we can calculate the number of moles of FeO by dividing the mass by the molar mass:
25.0 g / 71.844 g/mol = 0.348 moles of FeO.

3. Determine the stoichiometry of the reaction:
The chemical formula for iron oxide is FeO. By examining the formula, we can see that one mole of FeO contains one mole of iron (Fe).

4. Calculate the moles of iron (Fe):
Since the stoichiometry of FeO is 1:1 with iron (Fe), the number of moles of iron is also 0.348 moles.

5. Convert moles of iron to grams:
To find the mass of iron in grams, we multiply the number of moles of iron by its molar mass (55.845 g/mol) to get:
0.348 moles * 55.845 g/mol = 19.42 grams.

Hence, approximately 19.42 grams of iron can be recovered from 25.0 grams of FeO.