An ideal gas (volume 1.1m3, pressure 103600 Pa, temperature 400 K) undergoes an isothermal process during which it absorbs 2000 J of heat. How much did the entropy of the system increase?
To calculate the change in entropy, we need to use the equation:
ΔS = Q / T
Where:
ΔS is the change in entropy
Q is the heat absorbed by the system
T is the temperature at which the process occurs
In this case, the heat absorbed by the system is given as 2000 J, and the temperature is 400 K. Plugging these values into the equation, we can calculate the change in entropy:
ΔS = 2000 J / 400 K
ΔS = 5 J/K
Therefore, the entropy of the system increased by 5 J/K.