A force of 3000 N is applied to a 1500-kg car at rest. (a) what is its acceleration? (b) what will its velocity be 5 s later?
pray lang palagi si lord ang bahala sayu, makakamit morin ang goals mo sa buhay
F = ma
and
V -Vo = at
Use the first equation (rearranged algebraically) to caclulate the acceleration, a. Then use that "a" in the second equation to calculate the new velocity. The initial velocity (Vo) is zero.
To answer these questions, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The relationship is given by the equation:
a = F/m
where "a" represents acceleration, "F" represents the force acting on the object, and "m" represents its mass.
(a) To find the acceleration of the car, we need to divide the force applied by its mass:
a = 3000 N / 1500 kg
a = 2 m/s² (meters per second squared)
Therefore, the acceleration of the car is 2 m/s².
(b) To find the velocity of the car 5 seconds later, we need to use the equation of motion:
v = u + at
where "v" represents the final velocity, "u" represents the initial velocity, "a" represents the acceleration, and "t" represents time.
Given that the car is initially at rest (u = 0 m/s) and we know the acceleration (a = 2 m/s²), we can substitute these values into the equation:
v = 0 + (2 m/s²) * 5 s
v = 10 m/s (meters per second)
Therefore, the velocity of the car 5 seconds later will be 10 m/s.
You should be familiar with the equations
F = ma
and
V -Vo = at
Use the first equation (rearranged algebraically) to caclulate the acceleration, a. Then use that "a" in the second equation to calculate the new velocity. The initial velocity (Vo) is zero.