How many pi bonds and sigma bonds are present in ritalin?
The structure is here
http://en.wikipedia.org/wiki/Methylphenidate
so how many of each?
I counted for pi bonds and 18 sigma bonds is that correct?
To determine the number of pi bonds and sigma bonds present in Ritalin, we first need to understand its chemical structure. Ritalin's chemical name is methylphenidate.
The molecular formula for methylphenidate is C14H19NO2, which tells us it contains 14 carbon atoms, 19 hydrogen atoms, one nitrogen atom, and two oxygen atoms.
To determine the number of sigma (σ) bonds, we need to count the number of single covalent bonds present in the molecule. In methylphenidate, we have single bonds between carbon and hydrogen atoms (C-H), carbon and nitrogen atoms (C-N), carbon and oxygen atoms (C-O), and nitrogen and oxygen atoms (N-O).
Therefore, the number of sigma (σ) bonds in Ritalin is 14 (C-C) + 19 (C-H) + 1 (C-N) + 1 (C-O) + 1 (N-O) = 36 sigma (σ) bonds.
To determine the number of pi (π) bonds, we need to count the number of double bonds or triple bonds present in the molecule. In methylphenidate, there are no double bonds or triple bonds. Therefore, the number of pi (π) bonds in Ritalin is 0.
In summary, methylphenidate (Ritalin) has 36 sigma (σ) bonds and 0 pi (π) bonds.