what is the perimter of a rectangle. the length is 6 more than the width and the perimeter is 44
P = 2L + 2W
44 = 2(W + 6) + 2W
44 = 4W + 12
44-12 = 4W
32 = 4W
8 = W
How do you make 36 the area and 26 premeter
To find the perimeter of a rectangle, you need to know its length and width. In this case, we have some additional information: the length is 6 more than the width, and the perimeter is 44.
Let's use variables to represent the width and length of the rectangle. Let's say the width is "w." According to the statement, the length is 6 more than the width, so the length would be "w + 6."
The formula for the perimeter of a rectangle is given by: Perimeter = 2 * (Length + Width).
Substituting the values we have, we get: 44 = 2 * (w + 6 + w).
Simplifying the equation, we have: 44 = 2 * (2w + 6).
Now, we can solve for "w" by dividing both sides of the equation by 2: 22 = 2w + 6.
Next, we subtract 6 from both sides: 16 = 2w.
Finally, dividing both sides by 2, we get: w = 8.
Now that we know the value of "w," we can substitute it back into the formula to find the length: length = w + 6 = 8 + 6 = 14.
Therefore, the width of the rectangle is 8 and the length is 14. To find the perimeter, we substitute these values into the formula: Perimeter = 2 * (8 + 14) = 2 * 22 = 44.
So, the perimeter of the rectangle is 44 units.