Two particles of mass m1 = 1.0 kg and m2 = 2.6 kg are traveling with velocities v1 = 4.9, and v2 = 2.5 as shown in the figure below. What is the total momentum of this system? Be sure to give the magnitude and direction of the momentum. magnitude 1 kg · m/s
direction 2° above the x-axis
<<magnitude 1 kg · m/s
direction 2° above the x-axis>>
Is that your answer or part of the question?
I can't see your figure so can't tell what the angle is between the momentum vectors of the two masses. You know that the momentum of each is M*V. The direction of the momentum vector is the direction of the velocity.
Do the MV multiplications and the vector addition, if you haven't already.
To find the total momentum of the system, you need to calculate the momentum of each particle and then add them together. Recall that momentum is defined as the product of an object's mass and its velocity.
First, calculate the momentum of particle 1 (m1) using the formula:
momentum1 = mass1 * velocity1
momentum1 = 1.0 kg * 4.9 m/s = 4.9 kg·m/s
Next, calculate the momentum of particle 2 (m2):
momentum2 = mass2 * velocity2
momentum2 = 2.6 kg * 2.5 m/s = 6.5 kg·m/s
Now, you can find the total momentum by adding the individual momenta together:
total momentum = momentum1 + momentum2
total momentum = 4.9 kg·m/s + 6.5 kg·m/s = 11.4 kg·m/s
So, the total momentum of this system is 11.4 kg·m/s.
To determine the direction of the momentum, inspect the given figure. It states that the direction is 2° above the x-axis. This means that the total momentum is inclined at an angle of 2° with respect to the x-axis.