in the following total ionic equation, which ions are spectator ions?
Cu2+ (aq) + 2NO3-(aq)+2Na+(aq)+S2-(aq)--->CuS(s)+2NO3-(aq)+2Na+(aq)
Spectator ions are those that are common to both sides of the equation. Cu^+2, for example, is NOT a spectator ion. It's on one side but not the other (because it formed CuS and that is not soluble.) NO3^- is a spectator ion since it is on both sides . There is another one which I will let you identify.
Well, it looks like the copper (Cu2+), nitrate (NO3-), and sodium (Na+) ions are all participating in the reaction. The sulfur (S2-) ion, on the other hand, is the one that gets kicked out and joins with copper to form the solid CuS. So, in this case, the spectator ions would be the NO3- and Na+ ions. They're just hanging out on the side, watching the action, but not really taking part in the chemical change. It's like being the only sober person at a wild party - you're there, but you're not really involved in the madness.
To determine the spectator ions in the given total ionic equation, we need to identify which ions are present on both sides of the equation and do not participate in the reaction. These ions remain in solution and do not undergo any change.
In the total ionic equation provided:
Cu2+(aq) + 2NO3-(aq) + 2Na+(aq) + S2-(aq) ---> CuS(s) + 2NO3-(aq) + 2Na+(aq)
The ions NO3- and Na+ appear on both sides of the equation, meaning they are spectator ions. These ions do not cause or undergo any chemical change during the reaction.
Therefore, the spectator ions in the given equation are NO3- and Na+.
To determine the spectator ions in a total ionic equation, we need to identify the ions that appear on both sides of the equation, without undergoing any change or participating in the reaction.
In the given ionic equation, the ions that appear on both sides of the equation without changing are:
- NO3-(aq)
- 2Na+(aq)
These ions are called spectator ions because they do not participate in the reaction and remain in solution unchanged.