What is the acceleration of a modified atwood machine if the mass of the cart is 4 kg and the hanging mass is 11 kg. (g = 9.8 m/s2 - give your answer to one decimal point)
Please include the accepted abbreviated form of the appropriate unit. m/s2 = m/s/s
To find the acceleration of a modified Atwood machine, we can use the formula:
acceleration = (m2 - m1) * g / (m1 + m2)
where:
m1 = mass of cart
m2 = hanging mass
g = acceleration due to gravity (9.8 m/s^2)
In this case, the mass of the cart (m1) is 4 kg and the hanging mass (m2) is 11 kg. Let's plug these values into the formula.
acceleration = (11 kg - 4 kg) * 9.8 m/s^2 / (4 kg + 11 kg)
acceleration = 7 kg * 9.8 m/s^2 / 15 kg
acceleration ≈ 4.55 m/s^2
To one decimal point, the acceleration of the modified Atwood machine is approximately 4.6 m/s^2.