What is the temperature of 0.65 mol of gas at a pressure of 1.1 atm and a volume of 11.2 L?
Use
PV=nRT
P, V, n are in the question. R is the gas constant. Find T.
To determine the temperature of a gas, we can use the ideal gas law, which is given by the equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin
To find the temperature of the gas, we need to rearrange the equation to solve for T:
T = PV / (nR)
Now, let's plug in the values given in the problem:
P = 1.1 atm
V = 11.2 L
n = 0.65 mol
The ideal gas constant (R) is a constant value that depends on the units of pressure and volume being used. The units most commonly used for R are atm·L/mol·K. The value of R is approximately 0.0821 atm·L/mol·K.
Now, let's plug in the values into the equation:
T = (1.1 atm) * (11.2 L) / (0.65 mol * 0.0821 atm·L/mol·K)
By multiplying and dividing the values, we can simplify the equation:
T = (1.1 * 11.2) / (0.65 * 0.0821)
Calculating the expression:
T = 14.3 / 0.053365
T = 268.19 K
Therefore, the temperature of 0.65 mol of gas at a pressure of 1.1 atm and a volume of 11.2 L is 268.19 Kelvin.