Science Physics
A rock of mass 48 kg accidentally breaks loose from the edge of a cliff and falls straight down. The magnitude of the air resistance that opposes its downward motion is 275 N. What is the magnitude of the acceleration of the rock?
netforce=ma
48*g-275=ma solve for a
You can ask a new question or answer this question .
Similar Questions
Top answer:
Fn = Fr - Fa, Fn = 32*9.8 - 258 = 55.6 N.=Net force. a = Fn/m = 55.6 / 32 = 1.74 m/s^2.
Read more.
Top answer:
(Weight - 275 N)/Mass = acceleration Weight = 313.6 N a = (313.6-275)/32 = 1.2 m/s^2 This
Read more.
Top answer:
To find the magnitude of the acceleration of the rock, we need to use Newton's second law of motion,
Read more.
Top answer:
1) PE = mgh PE = 20 kg * 9.8 m/sec^2 *100m KE = PE KE = 1/2 * m*v^2 2) W=F x d F = mg Force = 55 x
Read more.
Top answer:
ignoring air resistance, vf^2=2gh 2. with a terminal velocity of 30m/s final KE=1/2 m 30^2 3. work
Read more.
Top answer:
1. We can use the following equation of motion to calculate the speed of the rock at the bottom of
Read more.
Top answer:
(a) PE = m•g•h (b) KE = PE (c) mv²/2 = PE, v =sqrt(2•PE/m)
Read more.
Top answer:
To determine the height of the cliff, we need to consider the motion of the rock and use the
Read more.
Top answer:
V^2 = Vo^2 + 2g*d. Vo^2 = V^2--2g*d Vo^2 = 0 - (-19.6)*20.6 = 403.76 Vo = 20.1 m/s. = Initial
Read more.
Top answer:
we don't have textbooks, and my teacher dosent teach, he just gives us really hard homework:(
Read more.
