A steel ball is tossed into the ocean and comes to rest at a depth of 2.40 km. Find its fractional change in volume, assuming the density of seawater is 1020 kg/m3.
To find the fractional change in volume of the steel ball, we need to compare its initial volume to its final volume at a depth of 2.40 km in the ocean.
First, let's find the initial volume of the steel ball. Since no information is provided about its size or shape, we'll assume it is a perfect sphere. The formula for the volume of a sphere is given by:
V = (4/3)πr^3
To find the radius (r) of the steel ball, we need to know its initial density and mass. However, the question does not provide this information. Without it, we cannot determine the initial volume accurately. If you have additional data about the steel ball, please provide it, and I'll be happy to assist you further.