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a computer company can sell 1000 computers if they price them at $500. The number sold will increase by 10 for every 1$ decrease in the price. The company has fixed cost of $100,000, and each computer costs $300 to produce. Find the price that will maximize the company's profit. How many computers will sell at this price?

  • math -

    let the number of $1 decreases be n
    number sold = 1000 + 10n
    price of each = 500 - n

    profit = (1000 + 10n)(500-n) - 300(1000+10n) - 100000

    expand this mess, differentiate it , then set that equal to zero

  • inter algebra -

    $102.00

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