convert 2(NH4)3PO4+3HgSO4=3(NH4)2SO4+Hg3(PO4)2 into complete ionic equation,then net ionic equation
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To convert the given chemical equation ( 2(NH₄)₃PO₄ + 3HgSO₄ → 3(NH₄)₂SO₄ + Hg₃(PO₄)₂) into a complete ionic equation and then a net ionic equation, you need to understand the concept of ionic compounds and dissociation.
1. Complete Ionic Equation:
In a complete ionic equation, all compounds that are soluble in water are written as separate ions.
The given equation is:
2(NH₄)₃PO₄ + 3HgSO₄ → 3(NH₄)₂SO₄ + Hg₃(PO₄)₂
First, determine the soluble compounds:
- (NH₄)₃PO₄: Ammonium phosphate, soluble.
- HgSO₄: Mercury(II) sulfate, soluble.
- (NH₄)₂SO₄: Ammonium sulfate, soluble.
Now, write the complete ionic equation by splitting these soluble compounds into their respective ions:
2NH₄⁺ + 3PO₄³⁻ + 3Hg²⁺ + 3SO₄²⁻ → 3NH₄⁺ + 2SO₄²⁻ + Hg₃(PO₄)₂
2. Net Ionic Equation:
In a net ionic equation, only the significant species participating in the reaction are considered. The spectator ions (ions that do not undergo any change) are removed.
Based on the complete ionic equation above, we can identify the spectator ions:
- NH₄⁺ and SO₄²⁻ ions appear on both sides of the equation without any change.
Remove the spectator ions, and the remaining ions represent the net ionic equation:
PO₄³⁻ + 3Hg²⁺ → Hg₃(PO₄)₂
Therefore, the net ionic equation for the reaction 2(NH₄)₃PO₄ + 3HgSO₄ → 3(NH₄)₂SO₄ + Hg₃(PO₄)₂ is PO₄³⁻ + 3Hg²⁺ → Hg₃(PO₄)₂.