How do you find the x and y intercept of 3x+0.5y=6?
I know you set x and y to 0.. and then divide by the other variable's number.
I think?
Could somebody explain how to find the intercepts of this problem?
Thank you
-Allyson
x intercept, when y is zero
3x=6
x=2
y intercept,when x is zero
.5y=6
y=12
When is y not 0?
y is not zero along the line 3x+.5y=6
To find the x-intercept, we set y to 0 and solve for x in the equation 3x + 0.5y = 6.
1. Substitute y with 0:
3x + 0.5(0) = 6
2. Simplify:
3x = 6
3. Divide both sides of the equation by 3:
x = 2
Therefore, the x-intercept is 2, meaning the line passes through the point (2, 0).
To find the y-intercept, we set x to 0 and solve for y in the same equation.
1. Substitute x with 0:
3(0) + 0.5y = 6
2. Simplify:
0.5y = 6
3. Divide both sides of the equation by 0.5:
y = 12
So the y-intercept is 12, meaning the line passes through the point (0, 12).
In summary, the x-intercept of the equation 3x + 0.5y = 6 is 2, and the y-intercept is 12.