# Math: Calculus

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Can someone help me out here with these two problem? I have know idea where to start.

1)The equation: 10(x-1)(x-2)(x-3)=1,
has three real solutions a<b<c

where
a=____, b=___ , and c=___.

Enter your answers with at least six correct digits beyond the decimal point.
Hint: Ask what the solutions are if the right hand side is 0 instead of 1, and use Newton's Method.

2) Find the smallest positive value of which satisfies -- x=4.100cos(2.800x)

Give the answer to four places of accuracy._________

Remember to calculate the trig functions in radian mode.

• Math: Calculus -

Mr. Pursley has answered both questions.

If you encounter difficulties, post in detail what they are.

• Math: Calculus -

Rewrite the equation in the form:
f(x)=0
For example
f(x)=x²-2=0
Calculate f'(x)=2x
Calculate
x1=x0-f(x0)/f'(x0)
=1-(1-2)/2
=1.5
Repeat until the desired accuracy is obtained:
x2=x1-f(x1)/f'(x1)
=1.5-(2.25-2)/(2*2.25)
=1.444
x3=x2-f(x2)/f'(x2)
=1.444-(0.085136)/2.888
=1.41452
...
Notice that the number of accurate figures of the solution doubles with every iteration.

Try the method with the given problems and post if you have difficulties.

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