Chemistry(I'm sooo confused here!)
posted by lavonne .
The Rydberg equation, with n1=1, predicts an ultraviolet series of spectral lines of atomic hydrogen. Which of the following wavelengths is not predicted by the equation: 1/ = (1.097 x 10(7) m  1) x (1/n1(2)1/n2(2)
a)182 nm
b)103 nm
c)97 nm
d) 95 nm
e) 91 nm
I know i posted this yesturday, but when I try to work this I'm not getting any of these choices so I don't know what I'm doing wrong!
We never did these in class, but they're on the homework so I need to know where I'm going wrong.

103 nm is from n1=1 and n2=3
98 nm is from n1=1 and n2=4
95 nm is from n1=1 and n2=5
I can't get 182 nm.
The limiting value for n1=1 and n2=infinity is 10^9/R = 91.5 nm so the wavelength cannot be smaller than this value.
So my choices are a) and e). c) is also not possible as the nearest value is 97.59 nm which rounds to 98 nm. 
182.3 comes from 1 and 2(close to 182)
102.55 comes from 1 and 3(close to 103)
97.23 comes from 1 and 4(close to 97)
94.95 comes from 1 and 5(close to 95)
93.76 comes from 1 and 6(not close to 91)
If you had shown your work we could have found the error. You DO need to learn where your mistake is. If you post another one at the top of the board to my attention, and show your work on any one of them, I will find the error for you. 
Bob
I still can't get 182!
1/L=1.097 x 10^7 x(1/1^21/2^2)
so
1/L=1.097 x 10^7x(10.25)
so
1/L=1.097 x 10^7 x0.75
1/L=8227500
L=1.22 x 10^7 m
or L=122 nm
Respond to this Question
Similar Questions

chemistry
Atomic hydrogen produces wellknown series of spectral lines in several regions of the electromagnetic spectrum. Each series fits the Rydberg equation with its own particular n sub 1 value. Calculate the value of n sub 1 (by trial … 
chemistry
Calulate the wavelengths (in nm) of the visible lines in the line spectrum of hydrogen using the Rydberg equation (nf = 2; ni = 3, 4, 5, and 6). 
Chemistry
Calulate the wavelengths (in nm) of the visible lines in the line spectrum of hydrogen using the Rydberg equation (nf = 2; ni = 3, 4, 5, and 6) I'm not sure how to do this; if someone could explain how to work it for one of the ni's, … 
chemistry
The Rydberg equation, with n1=1, predicts an ultraviolet series of spectral lines of atomic hydrogen. Which of the following wavelengths is not predicted by the equation: 1/ = (1.097 x 10(7) m  1) x (1/n1(2)1/n2(2) 
chemistry
The Rydberg equation, with n1=1, predicts an ultraviolet series of spectral lines of atomic hydrogen. Which of the following wavelengths is not predicted by the equation: 1/ = (1.097 x 10(7) m  1) x (1/n1(2)1/n2(2) a)182 nm b)103 … 
chemistry
Hydrogen exhibits several series of line spectra in different spectral regions. For example the Lyman series (nf = 1 in BalmerRydberg equation) occurs in the ultraviolet region while the Balmer (nf = 2) series occurs in the visible … 
Chemistry
Hydrogen exhibits several series of line spectra in different spectral regions. For example the Lyman series (nf = 1 in BalmerRydberg equation) occurs in the ultraviolet region while the Balmer (nf = 2) series occurs in the visible … 
Chemistry
Hydrogen exhibits several series of line spectra in different spectral regions. For example the Lyman series (nf = 1 in BalmerRydberg equation) occurs in the ultraviolet region while the Balmer (nf = 2) series occurs in the visible … 
Chemistry
An astrophysicist working at an observatory is interested in finding clouds of hydrogen in the galaxy. Usually hydrogen is detected by looking for the Balmer series of spectral lines in the visible spectrum. Unfortunately, the instrument … 
Chemistry Help! (Rydberg Equation)
a) According to the Rydberg equation, the line with the shortest wavelength in the emission spectrum of atomic hydrogen is predicted to lie at a wavelength (in nm) of _____ b) According to the Rydberg equation, the longest wavelength …