math grade 11
posted by priya .
A quadratic function is defined by
f(x)= 3x^2+4x-2. A linear function is defined by g(x)= mx-5. what values(s) of the slope of the line would make it a tangent to the parabola.
Slope of any function is first derivate of that function.
Quadratic function in your case have first dervate:
Linear function in your case have first dervate:
Line will be tangent of quadratic parabola when first derivates is egual.
-3*x^2=-3 Multiply with (-1)
3*x^2=3 Divided with 3
x1=-1 , x2=1
Slope for x1=6*x1+4=6*(-1)+4=-6+4=-2
Slope for x2=6*1+4=6+4=10