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A 125 kg crate rests on the flatbed of a truck that moves at a speed of 15.0 m/s around an unbanked curve whose radius is 66.0m. This crate does not slip relative to the truck. Obtain the magnitude of the static frictional force that the truck bed exerts on the crate.
If you could explain/show how you got the answer to this, it would be great!
Thanks

  • physics -

    The frictional force is compensating for the inward force to due to circular motion, for which you use the formula
    F=(mv^2)/r
    F=((125)(12^2))/66=273N
    pretty sure that's correct

  • physics -

    Thanks! That helped a lot

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