physics
posted by tom .
A baseball is hit at ground level. The ball reaches its maximum height above ground level 2.6 s after being hit. Then 2.1 s after reaching its maximum height, the ball barely clears a fence that is 96.4 m from where it was hit. Assume the ground is level.
(a) What maximum height above ground level is reached by the ball?
m
(b) How high is the fence?
m
(c) How far beyond the fence does the ball strike the ground?
m

Horizontal equation:
96.4=VicosTheta*4.7
Vertical equation:
h=ViSinTheta*4.74.9(4.7^2)
one last equation: at max height, vy=0
0=ViSinTheta*2.64.9(2.6^2)
Lets see. Solve the third equation for VisinTheta, put that into the second equation, solve for h (answer b)
then max height:
hmax=visintheta(2.6)4.9(2.6^2)
solve for hmax using the same expression you had in equation 3.
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