balance the followig example of a heterogeneous equilibrium and write its reaction quotient, Qc:

Question

balance the followig example of a heterogeneous equilibrium and write its reaction quotient, Qc:

S8 + F2=SF6
i've balanced it i think i got
S8 +24F2 =8SF6 but when i try it it keeps telling me that i'm wrong when i write out the Qc

Answer 1

i just need the reaction type for it

Answer 2

Your equation is balanced correctly. I suspect your Qc expression is wrong (this is just a guess) because you have included S8 (a solid). Does the equation, as it appears in the original question, have phases; for example,

S8(s) + 24F2(g) ==> 8SF6(g)

Then Qc = (SF6)^8/(F2)^24

The secret word in the problem is "hetergeneous" equilibrium
Solids and liquids are not included in those equilibrium expressions if they are solid/liquid in their normal state and the reaction is at T and P of their normal state.

Answer 3

To balance the given equation correctly, you need to ensure that the number of each element is the same on both sides of the equation. Let's balance it correctly:

S8 + 24F2 → 8SF6

Now, let's write the expression for the reaction quotient, Qc:

Qc = [SF6]^8 / ([S8] * [F2]^24)

In this expression, square brackets "[ ]" denote the concentration of each species.

Answer 4

To balance the equation S8 + F2 = SF6, you need to ensure that the number of atoms on both sides of the equation is the same. Let's break down the balancing process step by step:

1. Start with the unbalanced equation:
S8 + F2 = SF6

2. Count the number of atoms on each side of the equation:
On the left side: 8 sulfur (S) atoms, 2 fluorine (F) atoms
On the right side: 1 sulfur (S) atom, 6 fluorine (F) atoms

3. Balance the sulfur atoms:
Multiply S8 on the left side by 8, so you have 8 sulfur atoms on each side:
8S8 + F2 = 8SF6

4. Balance the fluorine atoms:
Multiply F2 on the left side by 12, so you have 24 fluorine atoms on each side:
8S8 + 24F2 = 8SF6

Now, let's calculate the reaction quotient, Qc. The reaction quotient is calculated similarly to the equilibrium constant, Kc, but it uses concentrations instead of equilibrium concentrations. Qc is calculated by writing the concentrations of the reactants and products, with the stoichiometric coefficients as exponents.

The reaction quotient, Qc, for the equation S8 + 24F2 = 8SF6 is written as follows:
Qc = [SF6]^8 / [S8]^8 * [F2]^24

In this equation, [SF6] represents the concentration of SF6, [S8] represents the concentration of S8, and [F2] represents the concentration of F2.