At equilibrium, [S(CH2CH2Cl)2] = 350 M, [SCl2]=.325M, and [C2H4] =.273 M for the reaction below. SCl2 + 2C2H4 = S(CH2CH2Cl)2
What is the Kc?
SCl2 + 2C2H4 = S(CH2CH2Cl)2'
Kc = [S(CH2CH2Cl)2]/(C2H4)^2(SCl2)
Substitute the numbers and solve for Kc.
To find the equilibrium constant (Kc) for the given reaction, we need to use the concentrations of the species at equilibrium.
The balanced chemical equation for the reaction is:
SCl2 + 2C2H4 → S(CH2CH2Cl)2
According to the given information, the equilibrium concentrations are:
[S(CH2CH2Cl)2] = 350 M
[SCl2] = 0.325 M
[C2H4] = 0.273 M
The equilibrium expression for this reaction is:
Kc = [S(CH2CH2Cl)2] / ([SCl2] * [C2H4]^2)
Now we can substitute the given concentrations into the equilibrium expression and calculate Kc:
Kc = 350 / (0.325 * (0.273)^2)
Kc ≈ 428.47 (rounded to two significant figures)
Therefore, the value of Kc for the given reaction is approximately 428.47.