Suppose you have a 10 watt fluorescent light bulb. If this light bulb is 6 % efficient in turning electricity into light, then how many photons are being emitted per second? Assume that average energy of all the photons emitted is 550 nm, thus you can treat all the photons as having the same energy as a 550 nm photon. Lastly, 1 watt = 1J/s

this is my answer
1.66E17
can you please tell me if i did it right

thank you

I have 1.66E18.

10 watt bulb @ 6% = 10*0.06 = 0.6 watt = 0.6 J/s. (I suspect we differ here.)

I used 6.626E-34 for h.
I used 3E8 for c.
I used 550E-9 for the wavelength.
This gave E = 3.61E-19
Then 0.6 J x 1 photon/3.61E-19 J =

To determine the number of photons being emitted per second, we need to follow a few steps:

Step 1: Calculate the energy consumption of the fluorescent light bulb.
Given that the bulb has a power of 10 watts, we can calculate the energy consumed per second using the equation:
Energy consumption = Power × Time

Since we are considering one second, the energy consumption is simply 10 joules (1 watt = 1 joule/second).

Step 2: Calculate the total energy of all the emitted photons.
Since the light bulb is 6% efficient in converting electricity into light, only 6% of the energy consumption is converted into light energy. Thus, the total light energy emitted per second is:
Total light energy = Energy consumption × Efficiency

Therefore, the total light energy emitted per second is 0.06 × 10 joules = 0.6 joules.

Step 3: Calculate the number of photons emitted.
To determine the number of photons, we need to use the equation:
Energy = Number of photons × Energy per photon

Rearranging the equation, we have:
Number of photons = Energy / Energy per photon

The average energy of the emitted photons is given as the energy of a 550 nm photon. We can calculate the energy per photon using the equation:
Energy per photon = Planck's constant × Speed of light / Wavelength

Substituting the given values (Planck's constant = 6.626 x 10^-34 J·s, Speed of light = 3 x 10^8 m/s, and wavelength = 550 nm = 550 x 10^-9 m), we can calculate the energy per photon.

Finally, divide the total light energy emitted per second by the energy per photon to obtain the number of photons emitted per second.

Now, let's calculate the result:

Energy per photon = (6.626 x 10^-34 J·s) × (3 x 10^8 m/s) / (550 x 10^-9 m)
Energy per photon = 3.62 x 10^-19 J

Number of photons = (0.6 J) / (3.62 x 10^-19 J)
Number of photons ≈ 1.66 x 10^18 photons per second

Based on the calculations, it seems that there was a mistake in your answer. The correct answer is approximately 1.66 x 10^18 photons being emitted per second.