a 25.0g sample of magnesium at 22.0 degrees C absorbs 356.3 J of heat. The temperature of magnesium rises to 36.5 degrees C. What is the specific heat of the magnesium?
To find the specific heat of magnesium, we can use the equation:
Q = m * c * ΔT
Where:
Q is the heat absorbed or released by the substance
m is the mass of the substance
c is the specific heat of the substance
ΔT is the change in temperature
In this case, we know:
Q = 356.3 J (heat absorbed)
m = 25.0 g (mass of magnesium)
ΔT = 36.5°C - 22.0°C = 14.5°C (change in temperature)
We can now rearrange the equation to solve for c:
c = Q / (m * ΔT)
Let's substitute the given values:
c = 356.3 J / (25.0 g * 14.5°C)
Now we can calculate the specific heat:
c ≈ 356.3 J / (362.5 g °C)
c ≈ 0.982 J/g°C (rounded to three significant figures)
Therefore, the specific heat of magnesium is approximately 0.982 J/g°C.