a helicopter of mass m has an acceleration of magnitude 0.12 upward. a)determine the force required to cause this aaceleration?
b) how much work is done by this force in moving the helicopter a distance deltay upward?
A.
Fnet=ma
Fx-Fg=ma
Fx=ma+Fg
Fx=m(0.12g)+mg
Fx=0.12mg+mg
Fx=1.12mg
B.
W=(Fx) (deltaY)
=1.12mg(delta)Y
a) To determine the force required to cause the given acceleration, we can use Newton's second law of motion:
Force = mass × acceleration
In this case, the acceleration is given as 0.12 upward. Since acceleration is a vector quantity, it has both magnitude and direction. The word "upward" indicates the direction, but the magnitude is not mentioned. We need the magnitude of the acceleration to calculate the force. Let's assume the magnitude of the acceleration is given as 0.12 m/s².
Therefore, the force required to cause this acceleration is:
Force = mass × acceleration
Force = m × 0.12
b) To determine the work done by the force in moving the helicopter a distance Δy upward, we can use the work-energy principle. The work done is calculated as the product of the force applied and the displacement in the direction of the force:
Work = force × displacement
In this case, the displacement is Δy (indicated as the distance moved upward).
Therefore, the work done by this force in moving the helicopter a distance Δy upward is:
Work = force × displacement
Work = (m × 0.12) × Δy
To determine the force required to cause the acceleration of the helicopter, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
a) The force required can be calculated using the formula:
Force = mass × acceleration
Substituting the given values:
Force = m × 0.12
b) The work done by this force in moving the helicopter a distance Δy upward can be calculated using the formula:
Work = Force × displacement
Substituting the given values:
Work = (m × 0.12) × Δy
Please note that the displacement, Δy, value is required to calculate the work done.