AP Calculus
posted by Anonymous .
A cardboard box of 108in cubed volume with a square base and no top constructed. Find the minimum area of the cardboard needed. (Optimization)

area= s^2+hs
Volume=s^2*h or 108/s^2=h
area= s^2+108/s
dA/ds= 2s108/s^2=0
2s^3=108
solve. 
Would the answer be 3.7?

you are looking for area, finding s is only the first step. Look at the area formula.

answer in the back of the book is 180in squared
but im not getting that answer
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