is these answers correct?
solve the equation: 2x^2 +8x - 17=(x +2)^2= x=-7,3
solve (v-5)^2-63=0, where v is a real number, simplify answer as much as possible. v=3 square root 7+5,-3 square root7+5
v``12.93725, -2.937254
use the quadratic formula to solve for x.
4x^2x-4=0
=x=1+squar root65/8 , 1-square root65/8=x``1.132782,-0.882782
thank yu
Need help quick please!! with provious questions on checking my answers.
the first one is correct
the second is correct
third, you have a typo in your equation
the answers are correct if the equation is
4x^2 - x - 4 = 0
Thanks Reiny!!
could you please check this for me? Thanks
use the quadratic formula to solve for x. 4x^2-x-4=0
x=1+ square root 65/8, 1- square root 65/8 = x``1.132782,-0.882782
sorry I have a few more and I need the answers quick!!
Find the value: ^3 square root -27= 9
Write the following in simlpified radical form: ^4 square root 80= 4
Solve for x, where x is real number: square 5x + 9= square root 9x + 13=27
SIMPLIFY:
32 3/5= 15 IS THIS CORRECT?
No, 32 3/5 cannot be simplified.
is this correct if not can you tell me wha it is please
32 3/5= 163/5
Let's go through each question and check the given answers step by step.
1. solve the equation: 2x^2 + 8x - 17 = (x + 2)^2, x = -7,3
To solve this equation, we need to expand the right side of the equation first:
(x + 2)^2 = (x + 2)(x + 2) = x^2 + 4x + 4
The original equation becomes:
2x^2 + 8x - 17 = x^2 + 4x + 4
Moving all terms to one side, we get:
2x^2 + 8x - 17 - x^2 - 4x - 4 = 0
Combining like terms:
x^2 + 4x - 21 = 0
Now, we can solve this quadratic equation. Factoring, completing the square, or using the quadratic formula are common methods.
Factoring:
(x + 7)(x - 3) = 0
Setting each factor equal to zero:
x + 7 = 0 or x - 3 = 0
Solving each equation separately:
x = -7 or x = 3
Hence, the correct solutions are x = -7 and x = 3. So, the answer provided, x = -7, 3, is correct.
2. solve (v - 5)^2 - 63 = 0, where v is a real number, simplify answer as much as possible. v = 3√7 + 5, -3√7 + 5
To solve this equation, we can start by isolating the squared term:
(v - 5)^2 = 63
Taking the square root of both sides (considering the positive and negative square roots):
v - 5 = ±√63
Simplifying the square root of 63:
v - 5 = ±√(9 * 7)
v - 5 = ±√9 * √7
v - 5 = ±3√7
Now we can solve for v by adding 5 to both sides:
v = 5 ± 3√7
Hence, the correct solution is v = 5 + 3√7 and v = 5 - 3√7. So, the answer provided, v = 3√7 + 5, -3√7 + 5, is correct.
3. Use the quadratic formula to solve for x: 4x^2x - 4 = 0
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 4, b = 0, and c = -4. Substituting these values into the formula, we have:
x = (-(0) ± √((0)^2 - 4(4)(-4))) / (2(4))
Simplifying:
x = (0 ± √(0 - (-64))) / 8
x = (0 ± √(0 + 64)) / 8
x = (0 ± √(64)) / 8
x = (0 ± 8) / 8
Solving the two cases:
Case 1: x = (0 + 8) / 8 = 8 / 8 = 1
Case 2: x = (0 - 8) / 8 = -8 / 8 = -1
So, the correct solutions are x = 1 and x = -1. The answer provided, x = 1 + √65/8, 1 - √65/8, is not correct. The correct solutions are x = 1.132782 and x = -0.882782.
I hope this clarifies the solutions for you. If you have any more questions, feel free to ask!