math
posted by lee .
is these answers correct?
solve the equation: 2x^2 +8x  17=(x +2)^2= x=7,3
solve (v5)^263=0, where v is a real number, simplify answer as much as possible. v=3 square root 7+5,3 square root7+5
v``12.93725, 2.937254
use the quadratic formula to solve for x.
4x^2x4=0
=x=1+squar root65/8 , 1square root65/8=x``1.132782,0.882782
thank yu

Need help quick please!! with provious questions on checking my answers.

the first one is correct
the second is correct
third, you have a typo in your equation
the answers are correct if the equation is
4x^2  x  4 = 0 
Thanks Reiny!!

could you please check this for me? Thanks
use the quadratic formula to solve for x. 4x^2x4=0
x=1+ square root 65/8, 1 square root 65/8 = x``1.132782,0.882782 
sorry I have a few more and I need the answers quick!!
Find the value: ^3 square root 27= 9
Write the following in simlpified radical form: ^4 square root 80= 4
Solve for x, where x is real number: square 5x + 9= square root 9x + 13=27 
SIMPLIFY:
32 3/5= 15 IS THIS CORRECT? 
No, 32 3/5 cannot be simplified.

is this correct if not can you tell me wha it is please
32 3/5= 163/5