if for times catherines age is sabtracted from 5 times joses age the difference is 32 years jose is sixteen find catherines age
Let J = Jose's age and C = Catherine's age.
5J - 4C = 32
5(16) - 4C = 32
Solve for C.
To find Catherine's age, we need to set up an equation based on the given information.
Let's denote Catherine's age as C and Jose's age as J. We are given that Jose is sixteen, so we can write J = 16.
According to the problem statement, if four times Catherine's age is subtracted from five times Jose's age, the difference is 32 years. We can express this mathematically as:
5J - 4C = 32
Substituting J = 16 into the equation above, we get:
5(16) - 4C = 32
80 - 4C = 32
Now, let's solve for C.
Subtract 80 from both sides:
-4C = 32 - 80
-4C = -48
Divide both sides by -4 to isolate C:
C = (-48) / (-4)
C = 12
Therefore, Catherine is 12 years old.